Question #25dff

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Answer 1 · 2017-07-01T22:30:26

#R_("AB")=(4R)/3#
#"You can also solve it using Delta-Star conversion."#

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#R_1" and " R_2 " are connected in series."R_8=R_1+R_2=2R#

#R_3" and " R_4 " are connected in series."R_9=R_3+R_4=2R#

#(R_8)/(R_6)=(2R)/R=2#

#(R_9)/(R_7)=(2R)/R=2#

#(R_8)/(R_9)=(2R)/(2R)=1#

#(R_6)/(R_7)=R/R=1#

Since the resistor ratios in the contacts are equal, no current flows through R5.

#R_8" and " R_9 " are connected in series."R_x=R_8+R_9=4R#

#R_6" and " R_7 " are connected in series."R_y=R_6+R_7=2R#

#R_x" and " R_y " are connected in parallel. "R_("AB")=(R_x*R_y)/(R_x+R_y)#

#R_("AB")=(4R*2R)/(4R+2R)#

#R_("AB")=(8R^2)/(6R)#

#R_("AB")=(4R)/3#