Question

How do you write the point slope form of an equation for a lint that passes through (-3,6) with m=0?

Answer 1

`y-6 = 0(x-(-3))`

Explanation:

Point slope form is this: `y-y_1=m(x-x_1)`, where the line passes through the point `(x_1, y_1)`, and has a slope of `m`.

Plugging in the values, we get:
`y-6 = 0(x-(-3))`

This is also just a horizontal line, or `y=6`.