Question

Question #03e92

Answer 1

`V_2 = 33.0` `"L"`

Explanation:

To solve this problem, we can use the temperature-volume relationship of gases, illustrated by Charles's law:

`(V_1)/(T_1) = (V_2)/(T_2)`

Remember that for all gas equation problems, the temperature must always be in units of Kelvin.

Let's convert both temperatures:

`T_1 = 19^"o""C" + 273 = 292` `"K"`

`T_2 = 122^"o""C" + 273 = 395` `"K"`

And the initial volume `V_1` is given as `24.4` `"L"`.

Plugging in known values, and solving for `V_2`, we have

`V_2 = (T_2V_1)/(T_1) = ((395cancel("K"))(24.4color(white)(l)"L"))/(292cancel("K")) = color(blue)(33.0` `color(blue)("L"`