Which of the following is the best description of the relationship between average kinetic energy and measurable quantities of an ideal gas?

#A)# It is directly proportional to temperature.
#B)# It is dependent on only the pressure.
#C)# It is related to the molar volume.
#D)# It is not related to pressure.

1 Answer
Jul 3, 2017

It's an ideal gas, but we still have to consider the equipartition theorem for the high-temperature limit of the average translational kinetic energy:

#bb(K_(tr,avg) = 3/2 nRT)#, in units of #"J"#

where the #3# was from the three cartesian degrees of freedom. #R = "8.314472 J/mol"cdot"K"# and #T# (i.e. temperature in #"K"#) are from the ideal gas law.

This tells us #K_(tr,avg)# explicitly depends on the mols of gas and the temperature it is at. Note that this is in units of #"J"#, not #"J/mol"#, so this is just the non-molar, average translational kinetic energy.

While it's true that the pressure is given by

#P = (nRT)/V = 2/3 (K_(tr,avg))/V#,

you should still find then that #bbA# is the best answer, being the most straightforwardly correct.

(There is a dependence on pressure, but it is NOT true that it is dependent on ONLY the pressure.)