Question

Question #d6bdb

Answer 1

The water displaced must have a mass of `9.25-8.2=1.05g`

Explanation:

This has a volume of `1.05cm^3`
(density is `0.998` at `20^o C`)

So the density of the metal is:
`rho(m)=m/V=9.25/1.05~~8.8g//cm^3`

The mass of the displaced gasoline was `9.25-8.36=0.84g`
`rho(g)=m/V=0.84/1.05~~0.80g//cm^3`

(everything rounded to 2 SF because of the `8.2`)