How do you solve #5(x-1)^2=50#?
1 Answer
Jul 4, 2017
Explanation:
#"divide both sides of the equation by 5"#
#5/5(x-1)^2=50/5#
#rArr(x-1)^2=10#
#color(blue)"take the square root of both sides"#
#sqrt((x-1)^2)=+-sqrt10larr" note plus or minus"#
#rArrx-1=+-sqrt10#
#"add 1 to both sides"#
#xcancel(-1)cancel(+1)=1+-sqrt10#
#rArrx=1+-sqrt10#
