How do you evaluate #\root[ 3] { 2187} + 2\root [ 3] { 3}#?

1 Answer
Shwetank Mauria
Jul 4, 2017

#root(3)2187+2root(3)3=11root(3)3#

Explanation:

#root(3)2187+2root(3)3#

= #root(3)(3xx3xx3xx3xx3xx3xx3)+2root(3)3#)

= #root(3)(ul(3xx3xx3)xxul(3xx3xx3)xx3)+2root(3)3#

= #3xx3xxroot(3)3+2root(3)3#

= #9root(3)3+2root(3)3#

= #11root(3)3#

Related questions
See all questions in Cube Root
Impact of this question
2221 views around the world
You can reuse this answer
Creative Commons License