Question

How do you evaluate `\frac { x ^ { 2} - 11x + 28} { x - 4} \cdot \frac { 2x } { x - 7}`?

Answer 1

`2x`

Explanation:

Factorise the first numerator to give `(x-4)(x-7)`

`((x-4)(x-7))/(x-4) xx (2x)/(x-7)`

The `(x-4)` will cancel with the one below and the `(x-7)` will cancel with the one to the bottom right

`(cancel((x-4))cancel((x-7)))/cancel((x-4)) xx (2x)/cancel((x-7))`

leaving `2x`