How do you solve this system of equation using the elimination method: #2x + 4y = 16, 2x - 4y = 0#?

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Answer 1 · 2017-07-04T22:37:16

See below.

We notice that there is a #+4y# and a #-4y#. If we added the two equations, we would eliminate #y#.

#2x+4y=16#
#+#
#2x-4y=0#

#4x=16#

#x=4#

Plugging this in,

#2(4)+4y=16#

#4y=8#

#y=2#

Thus, our solution set is #(4,2)#