Question

Question #9fafb

Answer 1

`y = 5, x = -3`

Explanation:

First, you need to remove a variable. Let's choose to get rid of x to solve for y in this case. Notice that if we multiply `-2x + 4y = 26` by 3, we can get rid of the x variables:

`6x + 5y = 7`
`3(-2x + 4y = 26)` = `-6x + 12y = 78`

We add the two equations:
`6x + 5y = 7`
`-6x + 12y = 78`

Which we'll get `17y = 85`

Divide both sides by 17 and we get `y = 5`

Then we choose one of two original equations to solve for x. Let's choose `6x + 5y = 7`

So plugging in y, we get `6x + 5(5) = 7`

Then we solve for x, so we get `6x = -24`

Divide by 6 for both sides and `x = -4`

You can double check if `x = -4, y = 5` is correct by plugging those two into the second equation, `-2x + 4y = 26`