Question

What is the length of the radius and the coordinates of the center of the circle defined by the equation `(x+7)^2+(y-3)^2=121`?

Answer 1

In

`(x - p)^2 + (y - q)^2 = r^2`

The radius is given by `r` and the centre by `(p, q)`. Hence, our centre is `(-7, 3)` and the radius is `11`. The graph of the relation confirms.

graph{(x+ 7)^2 + (y - 3)^2 = 121 [-10, 10, -5, 5]}

Hopefully this helps!

Answer 2

Radius is `11` and coordinates of center are `(-7,3)`

Explanation:

Equation of a circle whose center is `(h,k)` and radius is `r` is

`(x-h)^2+(y-k)^2=r^2`

As the equation `(x+7)^2+(y-3)^2=121` can be written as

`(x-(-7))^2+(y-3)^2=11^2`

Radius is `11` and coordinates of center are `(-7,3)`