How do you graph #x+2y=8# using intercepts?

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Answer 1 · 2017-07-06T18:09:06

The x-intercept is #(8,0)#.

The y-intercept is #(0,4)#.

Graph:

#x+2y=8#

The x-intercept is the value of #x# when #y=0#. The y-intercept is the value of #y# when #x=0#.

To get the x-intercept, substitute #0# for #y#.

#x+(2*0)=8#

#x=8#

The x-intercept is #(8,0)#.

To get the y-intercept, substitute #0# for #x#.

#0+2y=8#

#2y=8#

Divide by #2#.

#y=4#

The y-intercept is #(0,4)#.

You now have two points on the line. You can plot them and then draw a straight line through the points.

graph{x+2y=8 [-12.55, 12.76, -5.42, 7.24]}