How do you graph the linear function #f(x)=-1/2x+3#?

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Answer 1 · 2017-07-07T00:08:17

#x#-int #= (6,0)#

#y#-int #= (0,3)#

See graph in explanation

#f(x)=-1/2x+3 #

For the #x#-int, make #y=0#

#-1/2x+3=0#

#-1/2x=-3#

#x=6 #

For the #y#-int, make #x=0#

#y=3#

The intercepts are #(6,0)# and #(0,3)#.

graph{-0.5x+3 [-10, 10, -5, 5]}

This is a good example to use for graph scaling

-Fish