How do you solve the following linear system: #3x-y=23 , y+8x=11 #?

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Answer 1 · 2017-07-07T00:15:04

See below.

Notice the coefficients of the #y# term. It seems that adding is the simplest way to solve this.

#3x-y=23#
#+#
#8x+y=11#

#11x=34#

#x=34/11#

Plugging this in,

#3(34/11)-y=23#

#102/11-y=253/11#

#y=-151/11#

Thus, our solution is #(34/11,-151/11)#