How do you evaluate #3y - 4+ y + 20= 8+ 7y + 12- 5y#?

1 Answer
seol
Jul 10, 2017

#y=2#

Explanation:

Identify like terms

#\color(indianred)(3y)\color(seagreen)(-4)\color(indianred)(+y)\color(seagreen)(+20)=\color(seagreen)(8)\color(indianred)(+7y)\color(seagreen)(+12)\color(indianred)(-5y)#

Simplify both sides by adding like terms

  • #\color(indianred)(3y+y)\color(seagreen)(-4+20)=\color(seagreen)(8+12)\color(indianred)(+7y-5y)#
  • #\color(indianred)(4y)\color(seagreen)(+16)=\color(seagreen)(20)\color(indianred)(+2y)#

Reorganize so that like terms are alone on each side

  • #\color(indianred)(4y-2y)=\color(seagreen)(20-16)#
  • #\color(indianred)(2y)=\color(seagreen)(4)#

Divide to finish evaluation
#y=\color(seagreen)(4)/\color(indianred)(2)=2#

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