How do you graph #f(x)=(x+4)/(-2x-6)# using holes, vertical and horizontal asymptotes, x and y intercepts?

1 Answer
Jul 10, 2017

You may rewrite to #f(x)=-1/2 xx(x+4)/(x+3)#

Explanation:

The vertical asymptote will then be clear: #x=-3# as the demoninator may not be #=0#

If #x# gets larger and larger (both netaive or positive), the #+4# and #-3# matter less and the function will converge to:
#-1/2 xx x/x=-1/2#

So #y=-1/2# is the horizontal asymptote .
graph{(x+4)/(-2x-6) [-11.25, 11.25, -5.625, 5.625]}