What is the mole fraction of #LiCI# in a mixture of 0.564g #NaCl#, 1.52g #KCl# and 0.857g #LiCI#?

1 Answer
Doc048
Jul 11, 2017

Mole fraction #(X_(compound))# = #("moles compound"/"total moles of all compounds")#

Given:
#0.564 g NaCl# = #(0.564g)/(58(g/"mol"))# = #0.0097"mole"#

#1.52 g KCl# = #(1.52g)/(74(g/"mol"))# = #0.0205"mole"#

#0.857 g LiCl# = #(0.857g)/(42(g/"mol"))# = #0.0204"mole"#

#Sigma "moles" = (0.0097 + 0.0205 + 0.0204)"mole"# = #"0.0506mole"#

#X_(LiCl)# = #("moles LiCl")/(Sigma"moles")# = #(0.0204)/(0.0506)# = #0.04032#

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