Question

How do you find zeros of `f(x)=5x^3+6x^2+x`?

Answer 1

Zeros of `f(x)=5x^3+6x^2+x` are `0,-1` and `-1/5`

Explanation:

The function `f(x)=5x^3+6x^2+x` can be factorized as

`f(x)=x(5x^2+6x+1)`

`=x(5x^2+5x+x+1)`

`=x(5x(x+1)+1(x+1))`

i.e. `f(x)=x(5x+1)(x+1)`

Hence zeros of `f(x)=5x^3+6x^2+x` are `0,-1` and `-1/5`