How do you solve #\frac { 5( y - 3) } { 2} = - 4y#?

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Answer 1 · 2017-07-15T01:45:48

#y=15/13=1 2/13#

#(5(y-3))/2=-4y#

Multiply both sides by #2#.

#2xx(5(y-3))/2=2(-4y)#

#1cancel2xx(5(y-3))/(1cancel2)=-8y#

#5(y-3)=-8y#

Open the brackets and simplify.

#5y-15=-8y#

Add #8y# to both sides.

#5y+8y-15=8y-8y#

#13y-15=0#

Add #15# to each side.

#13y-15+15=15#

#13y=15#

Divide both sides by #13#.

#(13y)/13=15/13#

#(1cancel13y)/(1cancel13)=15/13#

#y=15/13=1 2/13#