Question #c2de7

3 Answers
Jul 15, 2017

#(a)color(white)(x)x^2=2#

Explanation:

#"note that "•color(white)(x)sqrtaxxsqrta=(sqrta)^2=a#

#x^2=(sqrt(sqrt5+2)+sqrt(sqrt5-2))^2/(sqrt(sqrt5+1))^2#

#"expand numerator/denominator using FOIL method"#

#x^2=(sqrt5+2+2(sqrt5+2)(sqrt5-2)+sqrt5-2)/(sqrt5+1)#

#color(white)(x^2)=(2sqrt5+2(5-4))/(sqrt5+1)=(2sqrt5+2)/(sqrt5+1)#

#"rationalise the denominator"#

#"multiply numerator/denominator by "(sqrt5-1)#

#((2sqrt5+2)(sqrt5-1))/((sqrt5+1)(sqrt5-1)#

#"expand numerator/denominator using FOIL"#

#=(10-2)/(5-1)=8/4=2#

#rArrx^2=2#

Jul 15, 2017

#(b)color(white)(x)1#

Explanation:

#"note that " sqrtaxxsqrtb=sqrt(ab)#

#"simplify each fraction by rationalising it's denominator"#

#color(blue)"fraction 1"#

#((7sqrt3)(sqrt10-sqrt3))/((sqrt10+sqrt3)(sqrt10-sqrt3))#

#=(7sqrt30-21)/(10-3)#

#=(7sqrt30-21)/7=sqrt30-3to(color(red)(1))#

#color(blue)"fraction 2"#

#((2sqrt5)(sqrt6-sqrt5))/((sqrt6+sqrt5)(sqrt6-sqrt5))#

#=(2sqrt30-10)/(6-5)#

#=2sqrt30-10to(color(red)(2))#

#color(blue)"fraction 3"#

#((3sqrt2)(sqrt15-3sqrt2))/((sqrt15+3sqrt2)(sqrt15-3sqrt2))#

#=(3sqrt30-18)/(15-18)#

#=(3sqrt30-18)/(-3)#

#=-sqrt30+6to(color(red)(3))#

#"put all this together gives"#

#sqrt30-3-(2sqrt30-10)-(-sqrt30+6)#

#=cancel(sqrt30)-3cancel(-2sqrt30)+10cancel(+sqrt30)-6#

#=1#

Jul 15, 2017

#(c)color(white)(x)sqrt10+sqrt5#

Explanation:

#"begin with simplifying the denominator"#

#"note the following"#

#•color(white)(x)sqrt(ab)hArrsqrtaxxsqrtb#

#"for example"#

#sqrt80=sqrt(16xx5)=sqrt16xxsqrt5=4sqrt5#

#rArrsqrt10+sqrt20+sqrt40-sqrt5-sqrt80#

#=sqrt10+2sqrt5+2sqrt10-sqrt5-4sqrt5#

#"collecting like radicals gives"#

#=3sqrt10-3sqrt5=3(sqrt10-sqrt5)#

#rArr15/(sqrt10+sqrt20+sqrt40-sqrt5-sqrt80)#

#=cancel(15)^5/(cancel(3)^1(sqrt10-sqrt5))=5/(sqrt10-sqrt5)#

#"multiply numerator/denominator by conjugate surd"#

#=(5(sqrt10+sqrt5))/((sqrt10-sqrt5)(sqrt10+sqrt5))#

#=(5sqrt10+5sqrt5)/(10-5)=(5sqrt10+5sqrt5)/5#

#=sqrt10+sqrt5#