Question

How do you simplify `\frac { 8a } { a ^ { 2} - 2a - 35} - \frac { 56} { a ^ { 2} - 2a - 35}`?

Answer 1

`= 8/(a+5)`

Explanation:

the denominators are already the same, so the two fractions can be written as one:

`(8a-56)/(a^2-2a-35)" "larr` factorise numerator and denominator

`= (8cancel((a-7)))/(cancel((a-7))(a+5))`

`= 8/(a+5)`