How do you solve #-8j = - 6- 9j#?

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Answer 1 · 2017-07-16T03:04:08

#j=-6#

#\color(olive)(-8j)=-6\color(olive)(-9j)#
#\color(olive)(-8j+9j)=-6\cancel(\color(olive)(-9j))\cancel(+9j)#
#\color(olive)(1j)=-6#

#j=-6#

Answer 2 · 2017-07-16T03:09:37

#j=-6#

Move the variable to one side by adding #9j# to both sides:

#-8j+9j=-6cancel(-9j+9j)#

#j=-6#

Answer 3 · 2017-07-16T03:12:46

#j# = -6

-8#j# = - 6 - 9#j#
[ bring #j# terms to LHS ]

-8#j# + 9#j# = - 6

#.:# #j# = #- 6 #