How do you solve #0.25( 4f - 3) = 0.05( 10f - 9)#?

1 Answer
Jul 16, 2017

#f=0.6#

Explanation:

#0.25(\color(blue)(4f)\color(red)(-3))=0.05(\color(seagreen)(10f)\color(palevioletred)(-9))#

  • distributive
    #\rArr0.25(\color(blue)(4f))+0.25(\color(red)(-3))=0.05(\color(seagreen)(10f))-0.05(\color(palevioletred)(-9))#
  • simplify
    #\rArr\color(blue)(1)f\color(red)(-0.75)=\color(seagreen)(0.5f)\color(palevioletred)(-0.45)#
    #\rArr\color(orange)(f)\color(skyblue)(-0.75)=\color(orange)(0.5f)\color(skyblue)(-0.45)#
  • combine like terms
    #\rArr\color(orange)(f-0.5f)=\color(skyblue)(0.75-0.45)#
    #\rArr\color(orange)(0.5f)=\color(skyblue)(0.30)#
  • get variable alone: #f=0.30\div0.5=0.6#
    #\thereforef=0.6#