Question

How many atoms are represented in 5.78 moles of `C_6H_12O_6` glucose?

Answer 1

Approx. `5.8xxN_Axx24`

Explanation:

`N_A` specifies `"Avogadro's number"` `-=` `6.022xx10^23*mol^-1`. And `"the mole"` this is simply another collective number like a dozen, or a score, or a gross........

And we gots `5.78*mol` of glucose.......

And thus the number of atoms is........

`5.78xx{6_"carbon atoms"+12_"hydrogen atoms"+6_"oxygen atoms"}xxN_A`

`138.72xxN_A` atoms in total........

Can you tell me the mass of this number of atoms? This is the next question you will be asked.