What is the moment of inertia of a pendulum with a mass of #3 kg# that is #11 m# from the pivot?

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Answer 1 · 2017-07-17T10:16:42

The moment of inertia is #=363kgm^2#

The mass of the pendulum is

#m=3kg#

The distance from the pivot is

#r=11m#

The moment of inertia is

#I=mr^2=3*11^2#

#=363kgm^2#