How do you solve the following system: #7y - 2x = 10, 11y + 3x = 4 #?

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Answer 1 · 2017-07-17T12:05:42

Arrange your equations, finding #x=-82/43# and #y=38/43#

Enlarge the first equation with 3 and the second with 2:

#21y - 6x = 30#
#22y + 6x = 8#

Combine these equations:

#21y + 22y = 38#

#43y = 38#

#y=38/43#

Now you can find x, put this y value into any original equation

#21times(38/43) - 6x = 30#

#-6x = 30 - (798/43)#

#-6x = 492/43#

#x = -492/(43times6)#

#x= -82/43#