How do you graph # -7y + 2x + 14# using intercepts?

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Answer 1 · 2017-07-18T12:28:43

The equation given is a line. #-7y+2x+14=0#

We put values for #x# and get values out for #y# or vise versa

So we find two point from which the line goes through

Let's start with #x=0#

#-7y+2x+14=0=>-7y+14=0=>y=2#

so the first point is #A_1(0,2)#

Now let's pu #y=0#

#-7y+2x+14=0=>2x+14=0=>x=-7#

So the second point is #A_2(-7,0)#

The graph is a line that goes through #A_1# and #A_2#
graph{-7y+2x+14=0 [-10, 10, -5, 5]}