How do you solve #- 7x + 2> 8#?

1 Answer
Jul 18, 2017

#x < \frac{6}{-7}#

Explanation:

1) Subtract 2 from both sides.
#-7x + 2 - 2 > 8 - 2#
#-7x > 6#

2) Divide -7 both sides.
#\frac{-7}{-7}x > \frac{6}{-7}#
#x > \frac{6}{-7}#

3) Change the symbol so that #x# is now less than #\frac{6}{-7}# because you have divided both sides by a negative number. #x < \frac{6}{-7}#