Question

How do you find the product `(3q-5r)^2`?

Answer 1

See a solution process below:

Explanation:

We can use the special case rule:

`(color(red)(a) - color(blue)(b))^2 = color(red)(a)^2 - 2color(red)(a)color(blue)(b) + color(blue)(b)^2`

Substituting `color(red)((3q))` for `color(red)(a)` and `color(blue)((5r))` for `color(blue)(b)` gives:

`(color(red)(3q) - color(blue)(5r))^2 => color(red)((3q))^2 - (2 * color(red)(3q) * color(blue)(5r)) + color(blue)((5r))^2 =>`

#9q^2 - 30qr + 25r^2