How do you evaluate #sqrt(b^2-4ac)# for a=-9, b=10, c=-1?

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Answer 1 · 2017-07-19T03:39:42

See a solution process below:

To evaluate this expression substitute:

#color(red)(-9)# for #color(red)(a)#

#color(blue)(10)# for #color(blue)(b)#

#color(green)(-1)# for #color(green)(c)#

#sqrt(color(blue)(b)^2 - 4color(red)(a)color(green)(c))# becomes:

#sqrt(color(blue)(10)^2 - (4 * color(red)(-9) * color(green)(-1))) =>#

#sqrt(100 - 36) =>#

#sqrt(64) =>#

#8#