Question

How do you multiply `\frac { 3x } { x + 2} \cdot \frac { ( x + 2) ^ { 2} } { 6x ^ { 2} }`?

Answer 1

`= (x+2)/x`

Explanation:

`\frac { 3x } { (x + 2)} \cdot \frac { ( x + 2) ^ { 2} } { 6x ^ { 2} }`

Usually we would multiply out the square of the bracket, but in this case there is the identical factor in the denominator, so we would rather cancel them.

`\frac { cancel3x } { cancel((x + 2))} \cdot \frac {cancel( ( x + 2))(x+2) } { cancel6^2x ^ { 2} }`

`=(x(x+2))/x^2" "larr` subtract the indices of `x`

`= (x+2)/x`