How do you evaluate #\sqrt { 45- 4( 3+ 6) }#?

1 Answer
Jul 20, 2017

See a solution process below:

Explanation:

First, evaluate the expression within the parenthesis:

#sqrt(45 - 4(color(red)(3) + color(red)(6))) => sqrt(45 - (4 * 9))#

Next, evaluate the multiplication within the parenthesis:

#sqrt(45 - (color(red)(4) * color(red)(9))) => sqrt(45 - 36)#

Then evaluate the expression within the radical:

#sqrt(color(red)(45) - color(red)(36)) = sqrt(9) = 3#