How do you factor out the GCF of #28x ^ { 2} y - 21x ^ { 3} y ^ { 2} + 35x ^ { 5} y ^ { 3}#?

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Answer 1 · 2017-07-20T08:16:51

#=7x^2y(4 -3xy +5x^3y^2)#

The process of factoring is exactly the opposite of removing the brackets by using the distributive law.

First identify which factors are common to all three terms.
Find the highest factor.

#28,21 and 35# each have a factor of #7#
Each term contains at least #x^2 and y#

The #GCF = 7x^2y#

Divide this factor out of each term and write the quotients in a bracket.

#28x ^ { 2} y - 21x ^ { 3} y ^ { 2} + 35x ^ { 5} y ^ { 3}#

#=7x^2y(4 -3xy +5x^3y^2)#