How do you solve #6( 6x + 9) - 3= 9x + 6#?

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Answer 1 · 2017-07-20T12:54:18

Distribute across the parenthesis and solve for #x#

#x = -5/3#

#6(6x +9) -3 = 9x+6#

#36 x + 54 -3 =9x+6" " # so now combine like terms

# 36x +51 = 9x + 6" "# subtract #9x and 51# from both sides

# 36x - 9x + 51 -51 = 9x -9x + 6 - 51" " # gives

# 27x = -45" "# dividing both sides by 27 gives

# (27x)/27 = (-45)/27# gives

#x = -5/3#

# x = - 1 2/3 #

Answer 2 · 2017-07-21T18:35:23

#6(6x+9)-3=9x+6#
#36x+54-3=9x+6#
#36x-9x=-54+3+6#
#27x=-54+9#
#27x=-45#
#x=frac(-45) 27#
Both are divisible by 9
#x=frac(-5) 3#