Question

Question #03a5b

Answer 1

`P=4184W`

Explanation:

So let's say that the ice was at `0""^oC` to start with , and the man gets it to `1""^oC`.

So `1kcal=4184J` is equal to the power needed for `1g` of water to get hotter by `1""^oC`.

The energy that was put in the ice therefore was :

`E=60*4184J=251040J`

The power is then :

`P=E/(Δt)=251040/60=4184W`