For #f(x) = 0.01(2)^x#, how do you fidn the average rate of change from #x=3# to #x=8#?

1 Answer
Jim H
Jul 21, 2017

Learn this: for any function #f#, the average rate of change from #x=a# to #x=b# is #(f(b)-f(a))/(b-a)#.

Explanation:

Do the arithematic:

#(f(b)-f(a))/(b-a) = (f(8)-f(3))/(8-3)#

# = (0.01(2^8) - 0.01(2^3))/5#

# = 0.01(256-8)/5#

# = 0.01 248/5#

# = 0.01 (49.6)#

# = 0.496#

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