A particle of mass 100 g is fired with velocity of 20 m/s making angle 30° with horizontal. When it reaches highest point, what is the magnitude of change in momentum?

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Answer 1 · 2017-07-21T02:01:07

1 #kg# #ms^-1#

Initial velocity #= vCos30i + vSin30j#

Final velocity #= vCos30i#

Change in momentum = #m*#(Final velocity- Initial velocity)

#Δp# = #0.1kg* [vCos30i - (vCos30i - vSin30j)]#

#Δp = 0.1kg * (-vSin30j)#

#Δp = 0.1kg * (-20ms^-1 × 1/2)j#

#Δp = -0.1kg × 10ms^-1j#

#Δp = -1 kg*ms^-1 j#

Magnitude of change in momentum is 1 kg #ms^-1#