Question #252eb

1 Answer
Jul 22, 2017

I am kind of confused about X2; is it #x^2# or #2x#? Anyways just remind me if the way I did it is wrong.

Explanation:

I am only inferring that this is the question, so just remind me if I am wrong.

#(x^2)/169+(y^2)/81=1#

This is actually an equation for an ellipse, so just figure out the vertex of it and you will get the answer; or you can also use the graphing method. Another tip is that the center for this ellipse is #(0,0)#, so we can use the #a# value to figure out the vertices, the solution to this problem.

The graph is a horizontal ellipse, since the larger #a# value is on the #x^2# side. So now, all we have to do is add the #a# value to the center:#(0,0)#.

So the answer is:
#(-13,0); (13,0)#