How do you graph #3x-y=7#?

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Answer 1 · 2017-07-22T04:11:35

Plot the points #(3.3,0) ; (0,-7)#
Join these two points you will get the curve.

Given -

#3x-y=7#

Find the two intercepts. Plot them and
join them with a straight line.

x-intercept
At #y=0#

#3x-0=7#
#x=7/3=3.3#
#(3.3,0)#

y-intercept
At #x=0#

#3(0)-y=7#
#y=-7#
#(0,-7)#

Plot the points #(3.3,0) ; (0,-7)#
Join these two points you will get the curve.

enter image source here

Answer 2 · 2017-07-22T04:16:51

I would rearrange the equation into standard form: #y = 3x-7#

This means that the line has a gradient (slope) of #3#, and a y-intercept of #-7#.

Graph the function by drawing a line through the point #(0,-7)# with a gradient of #3#.

#3x-y=7#

Subtract #3x# from both sides:

#-y=-3x+7#

Multiply both sides by #-1#:

#y = 3x-7#

This means that the line has a gradient (slope) of #3#, and a y-intercept of #-7#.