Question

What is the focus of a parabola whose equation is `x^2=1/5y`?

Answer 1

Simple. We know that `1/5 =4p`; and the p is the key concept to know in order to find the foci for a parabola.

Explanation:

Since it is `x^2`, and `4p` is positive we know it is a vertical parabola opening up and since there are no translations, we know that the vertex is at the origin. So all we have to do is add the `p` value to the y-value of the vertex coordinate.

`1/5=4p`
`p=1/20`

The foci coordinate:

`(0, 1/20)`