Question

What is the complex conjugate of `8 - sqrt3`?

Answer 1

Complex conjugate of `8-sqrt3` is `8-sqrt3`, itself.

Explanation:

Complex conjugate of a number `a+ib`, where `a`and `b` are two real numbers and `i` is imaginary number such that `i^2=-1`, is `a-ib`

Here we just have a real number `8-sqrt3` i.e. our complex number does not have imaginary part, whose sign changes in its conjugate.

Hence complex conjugate of `8-sqrt3` is `8-sqrt3`, itself.