Question

How do you simplify `(3b)/(-5c^-1)` and write it using only positive exponents?

Answer 1

`(3bc)/(-5)` or `-(3bc)/5`

Explanation:

`x^-a` generally equates to `1/x^a`, so:
`1/c^-1=(c^-1)^-1`

`=c^(-1\cdot(-1))` applying exponential multiplication
`=c^1` simplified; also equals `c`

replacing into original:

`(3b)/(-5c^-1)`
`(3bc)/(-5)` or `-(3bc)/5`