Question

How do you solve `(6x+2)^2+4=28`?

Answer 1

`x=-1/3+-1/3sqrt6`

Explanation:

`"isolate " (6x+2)^2`

`"subtract 4 from both sides"`

`rArr(6x+2)^2=24`

`color(blue)"take the square root of both sides"`

`sqrt((6x+2)^2)=+-sqrt24larr" note plus or minus"`

`rArr6x+2=+-2sqrt6larr" simplifying radical"`

`"subtract 2 from both sides"`

`rArr6x=+-2sqrt6-2`

`"divide both sides by 6"`

`rArrx=(-2+-2sqrt6)/6`

`color(white)(rArrx)=-1/3+-1/3sqrt6larrcolor(red)" exact values"`

`x~~ 0.483" to 3 dec. places"`

`"or " x~~-1.15" to 2 dec. places"`