An object with a mass of 14 kg is acted on by two forces. The first is F_1= < 5 N , 6 N> and the second is F_2 = < -9 N, 4 N>. What is the object's rate and direction of acceleration?

1 Answer
Jul 23, 2017

veca= <-2/7,5/7>

|veca|=sqrt29/7m/s^2

theta=111.8^o

Explanation:

Let's find the sum of the forces :

vec(F_1)+vec(F_2)=<5,6>+<-9,4> =<-4,10>

Now from the 2^"nd" Law of Newton :

ΣvecF=mveca=>veca=(ΣvecF)/m=1/14*<-4,10> =

<-2/7,5/7>

So veca= <-2/7,5/7>

The magnitude is |veca|=sqrt(4/49+25/49)=sqrt29/7m/s^2

The angle with the horizontal is theta=arctan((5/7)/(-2/7))=

arctan(-5/2)=111.8^o