How do you write a quadratic function in intercept form whose graph has x intercepts -3, -2 and passes through (-4, -6)?

Question

9044 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-25T12:08:36

The quadratic equation in intercept form is #y=-3(x+3)(x+2)#.

The quadratic equation in intercept form is #y=a(x-p)(x-q)#

where #p=-3 and q=-2# are x -intercepts . So The quadratic

equation in intercept form is #y=a(x+3)(x+2)#. The parabola

passes through #(-4,-6)# , which will satisfy the equation of

parabola. #:. -6 = a ( -4+3)(-4+2) or -6 = 2a # or

#a = -3 #. Hence the quadratic equation in intercept form is

#y=-3(x+3)(x+2)#.

graph{-3(x+3)(x+2) [-10, 10, -5, 5]} [Ans]