A train leaves a station and travels north at a speed of 75 mph. Two hours later, a second train leaves on a parallel track and travels north at 105 mph. How far from the station will they meet?
2 Answers
Jul 25, 2017
d = 525 miles, t = 5 hours
Explanation:
Equation for each train is d = v t
1st train d1 = 75 ( t+2 )
2nd train d2 = 105 t
When they meet, d1 = d2
75 ( t+2) = 105 t
Solving => t = 5
d1 = 75 ( 5 + 2 ) = 525 miles
d2 = 105 ( 5 ) = 525 miles
Jul 26, 2017
Using the kinematic expression for constant velocity
s = v t
The trains meet after these have traveled the same distance from the station.
Suppose both meet at time
1st train
s = 75 t ....(1)
2nd train
s = 105 ( t-2) .....(2)
Eliminating
t=s/75
Inserting this value in (2)
s = 105 ( s/75-2)
=>s = 105 ( (s-150)/75)
=>5s = 7 ( s-150)
=>2s = 7 xx150
=>s = 7 xx150/2
=>s = 7 xx75=525 " miles"