If a rocket with a mass of 4000 tons vertically accelerates at a rate of # 9/5 m/s^2#, how much power will the rocket have to exert to maintain its acceleration at 11 seconds?

Question

1534 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-25T19:28:16

#P=8,74*10^9W=8,74GW#

The power at a single moment is given by the formula :

#P=vF#

Let's find the force first :

#ΣF=ma=>F-mg=ma=>F=m(g+a)=#

#4*10^6(9,81+4,5)=176,6*10^6=1.766*10^8N#

Now let's find the velocity :

#v=at=4,5*11=49,5m/s#

The power is therefore :

#P=vF=49,5*1,766*10^8=87,4*10^8=8,74*10^9W=#

#8,74GW#