How do you multiply #4( 4b ^ { 2} + 3) ( 4b - 3)#?

1 Answer
smendyka
Jul 25, 2017

See a solution process below:

Explanation:

First, multiply the two sets of terms within parenthesis. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#4(color(red)(4b^2) + color(red)(3))(color(blue)(4b) - color(blue)(3))# becomes:

#4[(color(red)(4b^2) xx color(blue)(4b)) - (color(red)(4b^2) xx color(blue)(3)) + (color(red)(3) xx color(blue)(4b)) - (color(red)(3) xx color(blue)(3))]#

#4(16b^3 - 12b^2 + 12b - 9)#

Now, multiply each term within the parenthesis by the term outside the parenthesis:

#color(red)(4)(16b^3 - 12b^2 + 12b - 9)# becomes:

#(color(red)(4) xx 16b^3) - (color(red)(4) xx 12b^2) + (color(red)(4) xx 12b) - (color(red)(4) xx 9)#

#64b^3 - 48b^2 + 48b - 36#

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