How does #(costheta_1costheta_2-sintheta_1sintheta_2)+i(costheta_1sintheta_2+sintheta_1costheta_2)# become: #[cos(theta_1+theta_2)+isin(theta_1+theta_2)]#?
2 Answers
Jul 26, 2017
Please see below.
Explanation:
Recall
Hence
and
=
Hence
becomes
Jul 26, 2017
See below.
Explanation:
Using de Moivre's identity