How do you factor #3n ^ { 2} + 21n - 24#?

2 Answers
Jul 26, 2017

(x - 1)(3x + 24)

Explanation:

#y = 3n^2 + 21n - 24#.
Because a + b + c = 0, use shortcut.
The 2 factors are:
(x - 1) and #(x + c/a = x + 24/3)#
#y = 3(x - 1)(x + 24/3) = (x - 1)(3x + 24)#

Jul 26, 2017

#3(n-1)(n+8)#

Explanation:

Initially you can factor a 3 out of everything giving you :

#3(n^2+7n-8)#

Then simply factor #(n^2+7n-8)# which gives you :

#3(n-1)(n+8)#